The distance between two points (x1, y1) and (x2, y2) in a plane can be found using the distance formula derived from the Pythagorean theorem:

Distance = sqrt[(x2 - x1)² + (y2 - y1)²]

Here, the coordinates of point E are (8, -3) and the coordinates of point F are (-1, 9).

So, substituting these values into the formula, we get:

Distance = sqrt[(-1 - 8)² + (9 - (-3))²]
= sqrt[(-9)² + (12)²]
= sqrt[81 + 144]
= sqrt[225]
= 15

So, the distance between points E(8, -3) and F(-1, 9) is 15 units.

Question

The distance between two points (x1, y1) and (x2, y2) in a plane can be found using the distance formula derived from the Pythagorean theorem:

Distance = sqrt[(x2 - x1)² + (y2 - y1)²]

Here, the coordinates of point E are (8, -3) and the coordinates of point F are (-1, 9).

So, substituting these values into the formula, we get:

Distance = sqrt[(-1 - 8)² + (9 - (-3))²]
= sqrt[(-9)² + (12)²]
= sqrt[81 + 144]
= sqrt[225]
= 15

So, the distance between points E(8, -3) and F(-1, 9) is 15 units.

Knowee AI · Accepted Answer

The distance between two points (x1, y1) and (x2, y2) in a plane can be found using the distance formula derived from the Pythagorean theorem:

Distance = sqrt[(x2 - x1)² + (y2 - y1)²]

Here, the coordinates of point E are (8, -3) and the coordinates of point F are (-1, 9).

So, substituting these values into the formula, we get:

Distance = sqrt[(-1 - 8)² + (9 - (-3))²]
= sqrt[(-9)² + (12)²]
= sqrt[81 + 144]
= sqrt[225]
= 15

So, the distance between points E(8, -3) and F(-1, 9) is 15 units.

Find the distance between the pair of points. Upper E left parenthesis 8 comma negative 3 right parenthesis, Upper F left parenthesis negative 1 comma 9 right parenthesis