A car of mass 2000 kg which is travelling at 10 m/s crashes into a car of the same mass which is travelling at 5 m/s in the same direction. Calculate the total momentum of both cars after the collision.10,000 kg m/s40,000 kg m/s20,000 kg m/s30,000 kg m/s2A toy train of mass 0.5 kg which is travelling at 0.5 m/s crashes into a train of mass 1.0 kg which is travelling at 0.25 m/s in the opposite direction. Upon colliding, the trains stick together. Calculate their final velocity.0.5 m/s0.33 m/s0.17 m/s0 m/s3A car of mass 1500 kg which is travelling at 10 m/s is involved in a head-on collision with a car of mass 2000 kg which is travelling at 8 m/s. Upon colliding with one another, both cars stick together. With what velocity (magnitude and direction) will they move after the collision?8.86 m/s (in the direction in which the 2000 kg car was originally travelling)0.29 m/s (in the direction in which the 2000 kg car was originally travelling)8.86 m/s (in the direction in which the 1500 kg car was originally travelling)0.29 m/s (in the direction in which the 1500 kg car was originally travelling)4An airplane of mass 50,000 kg accelerates along a runway from rest to a velocity of 100 m/s in 20 seconds. Calculate the average resultant force which was acting on the plane during this time.100,000,000 N250,000 N0.04 N10,000 N5Which of the following is equal to the average resultant force which acts on an object while it is accelerating (or decelerating)?Its change in momentum multiplied by the time for which the force was actingThe time for which the force was acting divided by its change in momentumIts rate of change of momentum (its change in momentum divided by the time for which the force was acting)Its change in momentum (the difference between its initial and final momenta)6The action of a resultant force of 5 kN causes the momentum of a lorry to increase from 100,000 to 120,000 kg m/s. For how long was this resultant force acting on the lorry?44 seconds4 seconds24 seconds20 seconds
Question
A car of mass 2000 kg which is travelling at 10 m/s crashes into a car of the same mass which is travelling at 5 m/s in the same direction. Calculate the total momentum of both cars after the collision.10,000 kg m/s40,000 kg m/s20,000 kg m/s30,000 kg m/s2A toy train of mass 0.5 kg which is travelling at 0.5 m/s crashes into a train of mass 1.0 kg which is travelling at 0.25 m/s in the opposite direction. Upon colliding, the trains stick together. Calculate their final velocity.0.5 m/s0.33 m/s0.17 m/s0 m/s3A car of mass 1500 kg which is travelling at 10 m/s is involved in a head-on collision with a car of mass 2000 kg which is travelling at 8 m/s. Upon colliding with one another, both cars stick together. With what velocity (magnitude and direction) will they move after the collision?8.86 m/s (in the direction in which the 2000 kg car was originally travelling)0.29 m/s (in the direction in which the 2000 kg car was originally travelling)8.86 m/s (in the direction in which the 1500 kg car was originally travelling)0.29 m/s (in the direction in which the 1500 kg car was originally travelling)4An airplane of mass 50,000 kg accelerates along a runway from rest to a velocity of 100 m/s in 20 seconds. Calculate the average resultant force which was acting on the plane during this time.100,000,000 N250,000 N0.04 N10,000 N5Which of the following is equal to the average resultant force which acts on an object while it is accelerating (or decelerating)?Its change in momentum multiplied by the time for which the force was actingThe time for which the force was acting divided by its change in momentumIts rate of change of momentum (its change in momentum divided by the time for which the force was acting)Its change in momentum (the difference between its initial and final momenta)6The action of a resultant force of 5 kN causes the momentum of a lorry to increase from 100,000 to 120,000 kg m/s. For how long was this resultant force acting on the lorry?44 seconds4 seconds24 seconds20 seconds
Solution
Sure, I can help with that. Here are the answers to your questions:
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The total momentum of both cars after the collision is 30,000 kg m/s. This is calculated by adding the momentum of the first car (2000 kg * 10 m/s = 20,000 kg m/s) to the momentum of the second car (2000 kg * 5 m/s = 10,000 kg m/s).
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The final velocity of the toy train and the train after they stick together is 0.17 m/s. This is calculated by using the formula for momentum (mass * velocity) and setting the total momentum before the collision equal to the total momentum after the collision.
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After the collision, both cars will move with a velocity of 8.86 m/s in the direction in which the 2000 kg car was originally travelling. This is calculated by using the formula for momentum and setting the total momentum before the collision equal to the total momentum after the collision.
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The average resultant force which was acting on the plane during this time is 250,000 N. This is calculated by using the formula for force (mass * acceleration) and using the given values for mass and acceleration.
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The average resultant force which acts on an object while it is accelerating (or decelerating) is equal to its rate of change of momentum (its change in momentum divided by the time for which the force was acting).
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The resultant force was acting on the lorry for 4 seconds. This is calculated by using the formula for force (change in momentum / time) and solving for time.
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