A 3000 kg truck moving with a velocity of 10 m/s hits a 1000 kg parked car. The impact causes the 1000 kg car to be set in motion at 15 m/s. Assuming that momentum is conserved during the collision, what is the velocity of the truck immediately after the collision?*1 point5 m/s10 m/s17 m/s21 m/sSubmit
Question
A 3000 kg truck moving with a velocity of 10 m/s hits a 1000 kg parked car. The impact causes the 1000 kg car to be set in motion at 15 m/s. Assuming that momentum is conserved during the collision, what is the velocity of the truck immediately after the collision?*1 point5 m/s10 m/s17 m/s21 m/sSubmit
Solution
The principle of conservation of momentum states that the total momentum of a system of objects is constant if no external forces are acting on it.
Momentum is calculated as the product of mass and velocity.
Before the collision, the total momentum of the system is the momentum of the truck only (since the car is stationary), which is:
Momentum_truck_initial = mass_truck * velocity_truck = 3000 kg * 10 m/s = 30000 kg*m/s
After the collision, the total momentum of the system is the sum of the momenta of the truck and the car. We know the momentum of the car after the collision, but we don't know the final velocity of the truck (which we'll call v). So we can set up the following equation:
Momentum_truck_initial = Momentum_car_final + Momentum_truck_final 30000 kg*m/s = (1000 kg * 15 m/s) + (3000 kg * v)
Solving for v gives:
30000 kgm/s - 15000 kgm/s = 3000 kg * v 15000 kgm/s = 3000 kg * v v = 15000 kgm/s / 3000 kg v = 5 m/s
So the velocity of the truck immediately after the collision is 5 m/s.
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