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A bullet of mass 10 g travelling horizontally with a velocity of 150m/s collides with and sticks to a stationary wooden block of mass5 kg . Then they both move off together in the same straight line.Calculate the total momentum just before the impact and just afterthe impact. Also calculate the velocity of the combined objects .

Question

A bullet of mass 10 g travelling horizontally with a velocity of 150m/s collides with and sticks to a stationary wooden block of mass5 kg . Then they both move off together in the same straight line.Calculate the total momentum just before the impact and just afterthe impact. Also calculate the velocity of the combined objects .

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Solution

Sure, let's solve this step by step.

Step 1: Calculate the initial momentum of the system The initial momentum of the system is the momentum of the bullet just before the impact because the wooden block is stationary. Momentum is calculated as the product of mass and velocity.

The mass of the bullet is 10 g = 0.01 kg (since 1 g = 0.001 kg) The velocity of the bullet is 150 m/s

So, the initial momentum = mass of bullet * velocity of bullet = 0.01 kg * 150 m/s = 1.5 kg m/s

Step 2: Calculate the final momentum of the system The final momentum of the system is the momentum of the bullet and the wooden block moving together just after the impact. Since momentum is conserved in this collision, the final momentum of the system is equal to the initial momentum of the system.

So, the final momentum = initial momentum = 1.5 kg m/s

Step 3: Calculate the velocity of the combined objects The combined mass of the bullet and the wooden block is 0.01 kg + 5 kg = 5.01 kg

Since momentum = mass * velocity, we can rearrange the equation to solve for velocity:

Velocity = momentum / mass = 1.5 kg m/s / 5.01 kg = 0.3 m/s

So, the velocity of the combined objects just after the impact is 0.3 m/s.

This problem has been solved

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