A tennis ball of mass 50g is hit against a wall. It hits the wall going right at 5 ms-1 and rebounds to the left at 4 ms-1, changing its momentum by 0.45 kg m/s left.If the ball is in contact with the wall for 0.2 s what is the average force applied by the wall on the ball (your answer is a vector)?Question 2Select one:a.0.45 N Rightb.0.45 N Leftc.2.25 N Rightd.0.09 N Lefte.2.25 N Left
Question
A tennis ball of mass 50g is hit against a wall. It hits the wall going right at 5 ms-1 and rebounds to the left at 4 ms-1, changing its momentum by 0.45 kg m/s left.If the ball is in contact with the wall for 0.2 s what is the average force applied by the wall on the ball (your answer is a vector)?Question 2Select one:a.0.45 N Rightb.0.45 N Leftc.2.25 N Rightd.0.09 N Lefte.2.25 N Left
Solution
To solve this problem, we first need to understand the concept of momentum and how it changes. Momentum is the product of an object's mass and its velocity. The change in momentum (also known as impulse) is equal to the final momentum minus the initial momentum.
The initial momentum of the ball is its mass times its initial velocity. Since the ball is moving to the right, we can consider this direction as positive. So, the initial momentum is (0.05 kg) * (5 m/s) = 0.25 kg*m/s to the right.
The final momentum of the ball is its mass times its final velocity. Since the ball is moving to the left after hitting the wall, we consider this direction as negative. So, the final momentum is (0.05 kg) * (-4 m/s) = -0.20 kg*m/s to the left.
The change in momentum is the final momentum minus the initial momentum, which is -0.20 kgm/s - 0.25 kgm/s = -0.45 kg*m/s. The negative sign indicates that the change in momentum is to the left, which matches the given information.
The average force is the change in momentum divided by the time it takes for that change to occur. So, the average force is (-0.45 kg*m/s) / (0.2 s) = -2.25 N. The negative sign indicates that the force is to the left.
So, the correct answer is e. 2.25 N Left.
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