Jennifer hits a stationary 0.20-kg ball, and it leaves her racket at 40 m/s. Time-lapse photography shows that the ball was in contact with the racket for 40 ms.What average force did the ball exert on the racket?Group of answer choices1.20 N0.20 N1.20 kN0.20 kN
Question
Jennifer hits a stationary 0.20-kg ball, and it leaves her racket at 40 m/s. Time-lapse photography shows that the ball was in contact with the racket for 40 ms.What average force did the ball exert on the racket?Group of answer choices1.20 N0.20 N1.20 kN0.20 kN
Solution
To solve this problem, we need to use the formula for force, which is:
F = m*a
Where: F is the force, m is the mass, and a is the acceleration.
First, we need to find the acceleration. Acceleration is the change in velocity over time. In this case, the ball goes from 0 m/s to 40 m/s in 40 ms, which is 0.04 seconds.
So, a = Δv / t = (40 m/s - 0 m/s) / 0.04 s = 1000 m/s²
Then, we substitute the mass and acceleration into the force formula:
F = m*a = 0.20 kg * 1000 m/s² = 200 N
So, the average force the ball exerted on the racket is 200 N. Therefore, none of the provided answer choices are correct.
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