A 0.030 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.0030 s. What is the average force on the ball by the golf club?
Question
A 0.030 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.0030 s. What is the average force on the ball by the golf club?
Solution
To solve this problem, we need to use Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration (F = ma).
First, we need to find the acceleration of the golf ball. Acceleration is the change in velocity over time. In this case, the initial velocity of the golf ball is 0 m/s (since it starts from rest), and the final velocity is 34 m/s. The time it takes for this change to occur is 0.0030 s.
So, the acceleration (a) can be calculated as follows:
a = Δv / t a = (34 m/s - 0 m/s) / 0.0030 s a = 11333.33 m/s²
Then, we can find the force (F) using the formula F = ma:
F = 0.030 kg * 11333.33 m/s² F = 340 N
So, the average force exerted on the golf ball by the golf club is 340 Newtons.
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