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Jennifer hits a stationary 0.20-kg ball, and it leaves her racket at 40 m/s. Time-lapse photography shows that the ball was in contact with the racket for 40 ms.What average force did the ball exert on the racket?

Question

Jennifer hits a stationary 0.20-kg ball, and it leaves her racket at 40 m/s. Time-lapse photography shows that the ball was in contact with the racket for 40 ms.What average force did the ball exert on the racket?

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Solution

To solve this problem, we need to use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.

Step 1: Calculate the acceleration of the ball. Acceleration is the change in velocity divided by the time it takes for this change to occur. In this case, the ball goes from 0 m/s to 40 m/s in 40 ms, which is 0.04 seconds. So, the acceleration is (40 m/s - 0 m/s) / 0.04 s = 1000 m/s².

Step 2: Calculate the force exerted on the ball. According to Newton's second law, the force is the mass of the ball multiplied by its acceleration. So, the force is 0.20 kg * 1000 m/s² = 200 N.

Therefore, the average force that the ball exerted on the racket is 200 Newtons.

This problem has been solved

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