A 0.0450 kgkg golf ball initially at rest is given a speed of 33.0 m/sm/s when a club strikes.For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Kicking a soccer ball.Part AIf the club and ball are in contact for 2.20 msms, what is the magnitude of the average force acting on the ball?Express your answer with the appropriate units.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeFav𝐹av =
Question
A 0.0450 kgkg golf ball initially at rest is given a speed of 33.0 m/sm/s when a club strikes.For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Kicking a soccer ball.Part AIf the club and ball are in contact for 2.20 msms, what is the magnitude of the average force acting on the ball?Express your answer with the appropriate units.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeFav𝐹av =
Solution
To find the average force acting on the ball, we can use the formula for force, which is mass times acceleration (F = ma).
First, we need to find the acceleration of the golf ball. Acceleration is the change in velocity divided by the change in time. The initial velocity of the ball is 0 m/s, and the final velocity is 33.0 m/s. The time it takes for this change to occur is 2.20 ms, which is 0.0022 seconds (since 1 ms = 0.001 s).
So, the acceleration (a) of the ball is:
a = Δv / Δt a = (33.0 m/s - 0 m/s) / 0.0022 s a = 15000 m/s²
Now we can find the force. The mass (m) of the golf ball is 0.0450 kg. So, the force (F) is:
F = ma F = 0.0450 kg * 15000 m/s² F = 675 N
So, the magnitude of the average force acting on the ball is 675 Newtons.
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