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A,B and C play a game and the chances of their winning it in an attempt are (2/3), (1/2) and (1/4) respectively. A has the first chance, followed by B and then by C. This cycle is repeated till one of them wins the game. Then the probability that B wins is

Question

A,B and C play a game and the chances of their winning it in an attempt are (2/3), (1/2) and (1/4) respectively. A has the first chance, followed by B and then by C. This cycle is repeated till one of them wins the game. Then the probability that B wins is

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Solution

The problem can be solved using the concept of geometric progression (GP).

Step 1: Understand the problem The problem states that A, B, and C are playing a game. The probability of A winning is 2/3, B winning is 1/2, and C winning is 1/4. The game is played in a cycle (A, then B, then C) until one of them wins.

Step 2: Calculate the probability of each player winning in the first round The probability of A winning in the first round is 2/3. The probability of B winning in the first round is the probability of A not winning multiplied by the probability of B winning, which is (1 - 2/3) * (1/2) = 1/6. The probability of C winning in the first round is the probability of both A and B not winning multiplied by the probability of C winning, which is (1 - 2/3) * (1 - 1/2) * (1/4) = 1/24.

Step 3: Calculate the probability of each player winning in the second round The probability of each player winning in the second round is the same as the first round, but multiplied by the probability of no one winning in the first round. This is because the game is played in cycles until someone wins.

Step 4: Calculate the total probability of B winning The total probability of B winning is the sum of the probabilities of B winning in each round. This forms a geometric progression with the first term as 1/6 and the common ratio as the probability of no one winning in a round, which is (1 - 2/3) * (1 - 1/2) * (1 - 1/4) = 1/8.

The sum of an infinite geometric progression is given by the formula a / (1 - r), where a is the first term and r is the common ratio. Substituting the values, we get (1/6) / (1 - 1/8) = 2/7.

So, the probability that B wins is 2/7.

This problem has been solved

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