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A bookmaker is attempting to calculate the odds of a football team winning the next three matches (match A, match B and match C). They determine the probability of the team winning each respective match to be                P(A) =0.35  ;    P(B) =  0.65 ;   P(C) = 0.58 Assuming that these three events are independent, determine the probability that the team will(i) win all three matches      (Give your answer correct to 3 decimal places)                                                                                    (ii) win at least one match   (Give your answer correct to 3 decimal places)

Question

A bookmaker is attempting to calculate the odds of a football team winning the next three matches (match A, match B and match C). They determine the probability of the team winning each respective match to be                P(A) =0.35  ;    P(B) =  0.65 ;   P(C) = 0.58 Assuming that these three events are independent, determine the probability that the team will(i) win all three matches      (Give your answer correct to 3 decimal places)                                                                                    (ii) win at least one match   (Give your answer correct to 3 decimal places)

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Solution

(i) To find the probability of the team winning all three matches, we multiply the probabilities of each match since they are independent events.

P(A ∩ B ∩ C) = P(A) * P(B) * P(C) = 0.35 * 0.65 * 0.58 = 0.13205

So, the probability of the team winning all three matches is 0.132 (rounded to three decimal places).

(ii) To find the probability of the team winning at least one match, we can use the formula for the probability of the union of independent events, which is P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C).

However, a simpler way to calculate this is to find the probability of the team not winning any match and subtract it from 1.

The probability of the team not winning a match is (1 - P(A)) * (1 - P(B)) * (1 - P(C)) = (1 - 0.35) * (1 - 0.65) * (1 - 0.58) = 0.0913

So, the probability of the team winning at least one match is 1 - 0.0913 = 0.9087

So, the probability of the team winning at least one match is 0.909 (rounded to three decimal places).

This problem has been solved

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