In the last round of a chess tournament the final match is between Alice and Diego. The winner is the first player to win three games [sometimes called “best of 5”]. Assume that they are equally matched, so that each player has an equal probability of winning each game. What is the probability that the match will be finished after the first 3 games are played?
Question
In the last round of a chess tournament the final match is between Alice and Diego. The winner is the first player to win three games [sometimes called “best of 5”]. Assume that they are equally matched, so that each player has an equal probability of winning each game. What is the probability that the match will be finished after the first 3 games are played?
Solution
To solve this problem, we need to consider the possible outcomes where either Alice or Diego wins the first three games straight.
Since each game is independent and they are equally matched, the probability of Alice winning a game is 0.5, and the same goes for Diego.
- The probability of Alice winning three games in a row is (0.5) * (0.5) * (0.5) = 0.125.
- Similarly, the probability of Diego winning three games in a row is also 0.125.
Since these are mutually exclusive events (Alice and Diego can't both win three games in a row), we add the probabilities together to get the total probability of the match ending after three games.
So, the probability that the match will be finished after the first 3 games are played is 0.125 + 0.125 = 0.25 or 25%.
Similar Questions
A bookmaker is attempting to calculate the odds of a football team winning the next three matches (match A, match B and match C). They determine the probability of the team winning each respective match to be P(A) =0.35 ; P(B) = 0.65 ; P(C) = 0.58 Assuming that these three events are independent, determine the probability that the team will(i) win all three matches (Give your answer correct to 3 decimal places) (ii) win at least one match (Give your answer correct to 3 decimal places)
A,B and C play a game and the chances of their winning it in an attempt are (2/3), (1/2) and (1/4) respectively. A has the first chance, followed by B and then by C. This cycle is repeated till one of them wins the game. Then the probability that B wins is
In a tournament, a team has played 40 matches so far and won 30%30% of them. If they win 60%60% of the remaining matches, their overall win percentage will be 50%50%. Suppose they win 90%90% of the remaining matches, then the total number of matches won by the team in the tournament will be.
Two evenly matched basketball teams (call them A and B) compete in a best-of 7 championships (the first team to win 4 games wins the championship). Once the champion has been determined, no more games are played. In each game, there is a home team and an away team. The home team wins the game with probability p ≥ 1/2, independent of all previous games. Suppose that the first three games will be held at the home of team A and the last 4 (or fewer if they are not needed) are played at the home of team B.(a) Let X be the number of games won by team A out of the first 3 games. Specify the distribution of X.(b) Find the probability that only 4 games are played.(c) Which of the two teams is more likely to win the trophy? Explain why.(d) Give an expression for the probability that team A wins the trophy, and evaluate it when p = 0.55.(e) Let Y be the number of games won by team A. Find the probability mass function for Y.(f) Evaluate the expected number of games won by team A and the expected number of games played when p = 1/2.(g) Observe (via computations or simulation) that when p = 0.55 the expected number of games won by team A is larger than that of team B, even though team B is more likely to win the trophy.
Four matches are to be played in a chess tournament. In how many ways can result be decided?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.