What will the output of the following code snippet?void solve() { int a[] = {1, 2, 3, 4, 5}; int sum = 0; for(int i = 0; i < 5; i++) { if(i % 2 == 0) { sum += *(a + i); } else { sum -= *(a + i); } } cout << sum << endl;}215Syntax Error3
Question
What will the output of the following code snippet?void solve() { int a[] = {1, 2, 3, 4, 5}; int sum = 0; for(int i = 0; i < 5; i++) { if(i % 2 == 0) { sum += *(a + i); } else { sum -= *(a + i); } } cout << sum << endl;}215Syntax Error3
Solution
The output of the code will be 3.
Here's the step by step explanation:
- An integer array 'a' is declared with elements {1, 2, 3, 4, 5}.
- An integer 'sum' is declared and initialized to 0.
- A for loop is started which runs from i = 0 to i = 4.
- Inside the loop, there is an if-else condition. If 'i' is even, the 'i'th element of the array 'a' is added to 'sum'. If 'i' is odd, the 'i'th element of the array 'a' is subtracted from 'sum'.
- After the loop ends, the value of 'sum' is printed.
So, the calculation will be as follows:
sum = 0 + 1 (i = 0, even) sum = 1 - 2 (i = 1, odd) sum = -1 + 3 (i = 2, even) sum = 2 - 4 (i = 3, odd) sum = -2 + 5 (i = 4, even) sum = 3
Therefore, the output of the code will be 3.
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