What is the output of the following snippet? #include <iostream> using namespace std; int main(){ int i = 2; if (i--==1) cout << i; else cout << i + 1; return 0; } i + 1 2 3 1

The output of the given C++ code snippet will be 1.

Here's the step by step explanation:

1. The variable i is initialized with the value 2.
2. The if statement checks if i-- is equal to 1. The i-- operation decreases the value of i by 1 after the comparison. So, at the time of comparison, i is still 2, hence the condition i-- == 1 is false.
3. Since the condition in the if statement is false, the program goes to the else statement and executes cout << i + 1;. At this point, i is 1 (because of the i-- operation in the if statement), so i + 1 equals 2.
4. Therefore, the output of the program is 2.