What is the final output of the following code?int a = 5;int b = 10;int c = 3;for(int x =0; x< 5; x++){ a += 2; b -= 1; c *= 2;}cout<<"A is "<<a<<" and C is "<<c<<endl
Question
What is the final output of the following code?int a = 5;int b = 10;int c = 3;for(int x =0; x< 5; x++){ a += 2; b -= 1; c *= 2;}cout<<"A is "<<a<<" and C is "<<c<<endl
Solution
The final output of the code will be "A is 15 and C is 48".
Here's the step by step explanation:
- The initial values are a = 5, b = 10, and c = 3.
- The for loop will run 5 times because x starts from 0 and runs while x is less than 5.
- In each iteration of the loop:
- a is increased by 2 (a += 2), so after 5 iterations, a will be 5 + (2*5) = 15.
- b is decreased by 1 (b -= 1), but since b is not printed at the end, we don't need to calculate its final value.
- c is doubled (c *= 2), so after 5 iterations, c will be 3 * (2^5) = 48.
- At the end of the loop, the values of a and c are printed. So, the final output will be "A is 15 and C is 48".
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