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What will be the output of the following code snippet?void solve() { int a[] = {1, 2, 3, 4, 5}; int sum = 0; for(int i = 0; i < 5; i++) { if(i % 2 == 0) { sum += a[i]; } } cout << sum << endl;}

Question

What will be the output of the following code snippet?void solve() { int a[] = {1, 2, 3, 4, 5}; int sum = 0; for(int i = 0; i < 5; i++) { if(i % 2 == 0) { sum += a[i]; } } cout << sum << endl;}

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Solution

The output of the code will be 9.

Here's the step-by-step explanation:

  1. An integer array a is declared and initialized with the values {1, 2, 3, 4, 5}.
  2. An integer sum is declared and initialized with the value 0.
  3. A for loop is started which runs from i = 0 to i = 4.
  4. Inside the loop, there is an if condition that checks if i is even (i % 2 == 0). If i is even, the value of a[i] is added to sum.
  5. For i = 0, a[i] is 1, so 1 is added to sum.
  6. For i = 1, i is not even, so nothing is added to sum.
  7. For i = 2, a[i] is 3, so 3 is added to sum.
  8. For i = 3, i is not even, so nothing is added to sum.
  9. For i = 4, a[i] is 5, so 5 is added to sum.
  10. After the loop, sum is printed. The value of sum is 1 + 3 + 5 = 9. So, 9 is printed.

This problem has been solved

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