What will be the output of the following program?#include <iostream>using namespace std;int main()    {     int x, y;     x = 5;     y = x++ * ++x;     cout << x <<" " << y;     return 0;    }Select one:7  3536  3625  256  49

The output of the program will be "7 30".

Here's the step-by-step explanation:

1. The program starts with the declaration of two integer variables, x and y.
2. The variable x is assigned the value 5.
3. The expression x++ * ++x is evaluated for y. Here, x++ is a post-increment operation and ++x is a pre-increment operation.
4. In the post-increment operation (x++), the value of x is used first and then it is incremented. So, the value of x used here is 5 and then it becomes 6.
5. In the pre-increment operation (++x), the value of x is incremented first and then it is used. So, the value of x becomes 7 and then it is used.
6. Therefore, the expression becomes 5 * 7, which equals 35. But, due to the sequence point rule in C++, the post increment will be evaluated first. So, the expression becomes 6 * 5, which equals 30.
7. The value of y becomes 30.
8. The cout statement prints the values of x and y, which are 7 and 30 respectively.