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Mark looked at the statistics for his favorite baseball player, Jose Bautista. Mark looked at seasons when Bautista played 100 or more games and found that Bautista's probability of hitting a home run in a game is 0.173.If Mark uses the normal approximation of the binomial distribution, what will be the variance of the number of home runs Bautista is projected to hit in 100 games? Answer choices are rounded to the tenths place.17.33.80.814.3

Question

Mark looked at the statistics for his favorite baseball player, Jose Bautista. Mark looked at seasons when Bautista played 100 or more games and found that Bautista's probability of hitting a home run in a game is 0.173.If Mark uses the normal approximation of the binomial distribution, what will be the variance of the number of home runs Bautista is projected to hit in 100 games? Answer choices are rounded to the tenths place.17.33.80.814.3

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Solution

The variance of a binomial distribution is calculated by the formula npq, where n is the number of trials, p is the probability of success, and q is the probability of failure.

In this case, n = 100 (the number of games), p = 0.173 (the probability of hitting a home run), and q = 1 - p = 1 - 0.173 = 0.827 (the probability of not hitting a home run).

Substituting these values into the formula gives:

Variance = npq = 100 * 0.173 * 0.827 = 14.3

So, the variance of the number of home runs Bautista is projected to hit in 100 games is 14.3.

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