Runs scored by batsman in 5 one day matches are 50, 70, 82, 93, and 20. The standard deviation is ______Options25.7925.2925.6925.49

To find the standard deviation, follow these steps:

1. Find the mean (average) of the data set. Add all the numbers together and divide by the number of items in the set. In this case, (50 + 70 + 82 + 93 + 20) / 5 = 63.

2. Subtract the mean from each number in the data set and then square the result. This gives you the squared differences. For this data set, the squared differences are: (50-63)^2 = 169, (70-63)^2 = 49, (82-63)^2 = 361, (93-63)^2 = 900, (20-63)^2 = 1849.

3. Find the average of those squared differences. This is called the variance. So, (169 + 49 + 361 + 900 + 1849) / 5 = 665.6.

4. Take the square root of the variance to get the standard deviation. The square root of 665.6 is approximately 25.79.

So, the standard deviation of the runs scored by the batsman in 5 one day matches is approximately 25.79. Therefore, the correct option is 25.79.

To find the standard deviation, follow these steps:

1. Find the mean (average) of the data set. Add all the numbers together and divide by the number of items. In this case, (50 + 70 + 82 + 93 + 20) / 5 = 63.

2. Subtract the mean from each number to get the deviation of each number. This would give us -13, 7, 19, 30, -43.

3. Square each deviation. This gives us 169, 49, 361, 900, 1849.

4. Find the mean of these squared deviations. Add them all together and divide by the number of items. (169 + 49 + 361 + 900 + 1849) / 5 = 665.6.

5. Take the square root of this mean squared deviation. The square root of 665.6 is approximately 25.79.

So, the standard deviation is approximately 25.79. The closest option is 25.79.