The runs scored by a cricketer in ten matches are as follows: 47, 58, 96, 1, 6, 52, 6, 78, 102, and 1. The median is:a.47b.47.5c.49d.49.5
Question
The runs scored by a cricketer in ten matches are as follows: 47, 58, 96, 1, 6, 52, 6, 78, 102, and 1. The median is:a.47b.47.5c.49d.49.5
Solution
To find the median of a set of numbers, you first need to arrange the numbers in order from least to greatest. If there is an odd number of observations, the median is the middle number. If there is an even number of observations, the median is the average of the two middle numbers.
Here are the runs scored by the cricketer in ten matches arranged in ascending order: 1, 1, 6, 6, 47, 52, 58, 78, 96, 102.
Since there are 10 observations (an even number), we find the median by averaging the two middle numbers. The two middle numbers in this case are 47 and 52.
So, the median is (47 + 52) / 2 = 49.5.
Therefore, the answer is d. 49.5.
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