Runs scored by batsman in 5 one day matches are 50, 70, 82, 93, and 20. The standard deviation is ______Options25.6925.4925.7925.29
Question
Runs scored by batsman in 5 one day matches are 50, 70, 82, 93, and 20. The standard deviation is ______Options25.6925.4925.7925.29
Solution
To find the standard deviation, follow these steps:
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Find the mean (average) of the data set. Add all the numbers together and divide by the number of items. In this case, (50 + 70 + 82 + 93 + 20) / 5 = 63.
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Subtract the mean from each number to get the deviation of each number. This gives us -13, 7, 19, 30, -43.
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Square each deviation to get 169, 49, 361, 900, 1849.
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Find the mean of these squared deviations. (169 + 49 + 361 + 900 + 1849) / 5 = 665.6.
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Take the square root of this mean squared deviation. The square root of 665.6 is approximately 25.79.
So, the standard deviation is 25.79.
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