Calculate the volume of 3.00 g of carbon dioxide gas at 284K and 129.5 kPa.Give your answer in litres to three significant figures. Do not include units.

To solve this problem, we will use the ideal gas law equation, which is PV = nRT.

1. First, we need to find the number of moles (n) of carbon dioxide (CO2). The molar mass of CO2 is approximately 44.01 g/mol. So, n = mass/molar mass = 3.00 g / 44.01 g/mol = 0.068 mol.

2. Next, we need to convert the pressure from kPa to atm because R (the ideal gas constant) is usually given in atm. 1 atm = 101.325 kPa, so P = 129.5 kPa * (1 atm / 101.325 kPa) = 1.28 atm.

3. The temperature is given in Kelvin (K), so no conversion is needed. T = 284 K.

4. Now we can plug these values into the ideal gas law equation. We'll use the value of R = 0.0821 Latm/molK. So, V = nRT/P = 0.068 mol * 0.0821 Latm/molK * 284 K / 1.28 atm = 1.43 L.

So, the volume of 3.00 g of carbon dioxide gas at 284K and 129.5 kPa is 1.43 litres.