Calculate the volume of 3.00 g of carbon dioxide gas at 302K and 149.2 kPa.
Question
Calculate the volume of 3.00 g of carbon dioxide gas at 302K and 149.2 kPa.
Solution
To calculate the volume of a gas, we can use the ideal gas law, which is PV = nRT.
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First, we need to find the number of moles (n) of carbon dioxide (CO2). The molar mass of CO2 is approximately 44.01 g/mol. So, n = mass/molar mass = 3.00 g / 44.01 g/mol = 0.068 mol.
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Next, we need to convert the pressure from kPa to atm because R (the ideal gas constant) is usually given in terms of atm. 1 atm = 101.325 kPa, so P = 149.2 kPa * (1 atm / 101.325 kPa) = 1.47 atm.
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Now we can plug the values into the ideal gas law. We'll use R = 0.0821 Latm/molK. So, V = nRT/P = (0.068 mol * 0.0821 Latm/molK * 302 K) / 1.47 atm = 1.12 L.
So, the volume of 3.00 g of carbon dioxide gas at 302K and 149.2 kPa is approximately 1.12 liters.
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