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On analysis a certain compound was found to contain iodine and oxygen in the ratio of 254 gm of iodine (atomic mass 127) and 80 gm oxygen (at mass = 16). What is the formula of the compound. IO I2O I5O3 I2O5

Question

On analysis a certain compound was found to contain iodine and oxygen in the ratio of 254 gm of iodine (atomic mass 127) and 80 gm oxygen (at mass = 16). What is the formula of the compound. IO I2O I5O3 I2O5

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Solution

To find the formula of the compound, we need to determine the ratio of the number of atoms, not the ratio of their masses.

  1. First, we calculate the number of moles of each element using the formula: number of moles = mass / atomic mass.

For iodine: number of moles = 254 gm / 127 gm/mole = 2 moles

For oxygen: number of moles = 80 gm / 16 gm/mole = 5 moles

  1. Then, we write the ratio of the number of moles, which gives us the subscript numbers in the formula of the compound.

The ratio of iodine to oxygen is 2:5.

Therefore, the formula of the compound is I2O5.

This problem has been solved

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