Determine the mass of oxygen in 18.54 g of the organic compound, C4H10O.
Question
Determine the mass of oxygen in 18.54 g of the organic compound, C4H10O.
Solution
Sure, here are the steps to determine the mass of oxygen in 18.54 g of the organic compound, C4H10O:
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First, we need to calculate the molar mass of C4H10O. The molar mass of carbon (C) is approximately 12.01 g/mol, hydrogen (H) is approximately 1.01 g/mol, and oxygen (O) is approximately 16.00 g/mol.
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Multiply the molar mass of each element by the number of atoms of that element in the compound:
- Carbon: 12.01 g/mol x 4 = 48.04 g/mol
- Hydrogen: 1.01 g/mol x 10 = 10.10 g/mol
- Oxygen: 16.00 g/mol x 1 = 16.00 g/mol
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Add these values together to get the molar mass of C4H10O:
- 48.04 g/mol + 10.10 g/mol + 16.00 g/mol = 74.14 g/mol
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Now, we need to find out what fraction of this molar mass is due to oxygen. To do this, divide the molar mass of oxygen by the molar mass of the compound:
- 16.00 g/mol ÷ 74.14 g/mol = 0.2158 (or 21.58%)
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Finally, to find the mass of oxygen in 18.54 g of the compound, multiply the total mass of the compound by the fraction of the mass that is due to oxygen:
- 18.54 g x 0.2158 = 4.00 g
So, the mass of oxygen in 18.54 g of C4H10O is approximately 4.00 g.
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