The human body contains around 0.025 g of iodine molecules, I2. Which of thefollowing shows the number of iodine atoms in 0.025 g of I2?The Avogadro constant is 6.02 × 1023 mol–1 .A 0 025126 9 6 02 10 23.. .× ×B 0 025253 8 6 02 10 23.. .× ×C 253 80 025 6 02 10 23.. .× ×D 126 90 025 6 02 10 2

The question is asking for the number of iodine atoms in 0.025 g of I2.

Step 1: First, we need to find the molar mass of I2. The atomic mass of iodine (I) is approximately 126.9 g/mol. Since I2 is a molecule made up of two iodine atoms, its molar mass is 2*126.9 = 253.8 g/mol.

Step 2: Next, we need to convert the mass of I2 in grams to moles. We can do this using the formula:

Number of moles = mass (g) / molar mass (g/mol)

So, the number of moles of I2 is 0.025 g / 253.8 g/mol = 9.85 x 10^-5 mol.

Step 3: Finally, we need to find the number of atoms in this amount of I2. We can do this using Avogadro's number, which states that one mole of any substance contains 6.02 x 10^23 entities (atoms, in this case).

Number of atoms = number of moles x Avogadro's number

So, the number of iodine atoms in 0.025 g of I2 is 9.85 x 10^-5 mol x 6.02 x 10^23 atoms/mol = 5.93 x 10^19 atoms.

Therefore, none of the given options (A, B, C, D) are correct. The correct answer should be approximately 5.93 x 10^19 atoms.