What will be the output of the following Python code?1. def foo():2. try:3. print(1)4. finally:5. print(2)6. 7. foo()
Question
What will be the output of the following Python code?1. def foo():2. try:3. print(1)4. finally:5. print(2)6. 7. foo()
Solution
The output of the given Python code will be:
1 2
Here's the step by step explanation:
-
The function
foo()is defined. Inside this function, there is atryblock and afinallyblock. -
The
tryblock contains a print statement that prints the number 1. -
The
finallyblock contains a print statement that prints the number 2. Thefinallyblock is always executed regardless of whether an exception occurred in thetryblock or not. -
After defining the function, it is called with
foo(). -
When
foo()is called, it first executes thetryblock, which prints out 1. -
Then it executes the
finallyblock, which prints out 2.
So, the output of this code is 1 followed by 2.
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