What will be the output of the following Python code?def foo(): total += 1 return totaltotal = 0print(foo()) 01errornone of the mentioned
Question
What will be the output of the following Python code?def foo(): total += 1 return totaltotal = 0print(foo()) 01errornone of the mentioned
Solution
The output of the given Python code will be an error. This is because the variable 'total' is not defined in the local scope of the function 'foo'. In Python, variables referenced inside a function are implicitly global. If a variable is assigned a new value anywhere within the function’s body, it’s assumed to be a local. If a variable is ever assigned a new value inside the function, the variable is implicitly local, and you need to explicitly declare it as 'global'. Hence, when we try to increment the 'total' variable inside the function 'foo', Python assumes it to be a local variable and since it is not defined in the local scope, it throws an error.
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