The output of the given Python code will be:

3
1

Here's the step by step explanation:

1. The function `foo` is defined to take two arguments: `fname` and `val`. Inside the function, it prints the result of calling `fname(val)`.

2. The function `foo` is first called with `max` as `fname` and `[1, 2, 3]` as `val`. The `max` function returns the maximum value in the list, which is 3. So, `3` is printed.

3. The function `foo` is then called with `min` as `fname` and `[1, 2, 3]` as `val`. The `min` function returns the minimum value in the list, which is 1. So, `1` is printed.

Question

The output of the given Python code will be:

3
1

Here's the step by step explanation:

1. The function `foo` is defined to take two arguments: `fname` and `val`. Inside the function, it prints the result of calling `fname(val)`.

2. The function `foo` is first called with `max` as `fname` and `[1, 2, 3]` as `val`. The `max` function returns the maximum value in the list, which is 3. So, `3` is printed.

3. The function `foo` is then called with `min` as `fname` and `[1, 2, 3]` as `val`. The `min` function returns the minimum value in the list, which is 1. So, `1` is printed.

Knowee AI · Accepted Answer

The output of the given Python code will be:

3
1

Here's the step by step explanation:

1. The function `foo` is defined to take two arguments: `fname` and `val`. Inside the function, it prints the result of calling `fname(val)`.

2. The function `foo` is first called with `max` as `fname` and `[1, 2, 3]` as `val`. The `max` function returns the maximum value in the list, which is 3. So, `3` is printed.

3. The function `foo` is then called with `min` as `fname` and `[1, 2, 3]` as `val`. The `min` function returns the minimum value in the list, which is 1. So, `1` is printed.

What will be the output of the following Python code?def foo(fname, val): print(fname(val))foo(max, [1, 2, 3])foo(min, [1, 2, 3]) 3 11 3errornone of the mentioned

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