Show that the following relations for the group velocity are true: ๐ฃ๐ = โ๐2 ๐๐๐๐;
Question
Show that the following relations for the group velocity are true: ๐ฃ๐ = โ๐2 ๐๐๐๐;
Solution
To show that the relation ๐ฃ๐ = โ๐2 ๐๐/๐๐ for the group velocity is true, we can follow these steps:
Step 1: Start with the definition of the group velocity, which is given by ๐ฃ๐ = ๐๐/๐๐, where ๐ is the angular frequency and ๐ is the wave number.
Step 2: Express the angular frequency ๐ in terms of the wavelength ๐ and the frequency ๐ using the relation ๐ = 2๐๐.
Step 3: Differentiate the expression for ๐ with respect to ๐ using the chain rule. We have ๐๐/๐๐ = ๐๐/๐๐ * ๐๐/๐๐.
Step 4: Rearrange the expression to solve for ๐๐/๐๐. We get ๐๐/๐๐ = ๐๐/๐๐ / ๐๐/๐๐.
Step 5: Substitute the expression for ๐๐/๐๐ from step 3 into the equation from step 4. We have ๐๐/๐๐ = ๐๐/๐๐ * ๐๐/๐๐ / ๐๐/๐๐.
Step 6: Simplify the expression by canceling out the ๐๐/๐๐ terms. We are left with ๐๐/๐๐ = ๐๐/๐๐.
Step 7: Substitute the expression for ๐ from step 2 into the equation from step 6. We have ๐(2๐๐)/๐๐ = ๐๐/๐๐.
Step 8: Differentiate the expression for ๐ with respect to ๐. We have ๐๐/๐๐.
Step 9: Substitute the expression for ๐๐/๐๐ from step 8 into the equation from step 7. We have ๐(2๐๐)/๐๐ = ๐๐/๐๐ = ๐๐/๐๐.
Step 10: Rearrange the equation to solve for ๐๐/๐๐. We get ๐๐/๐๐ = ๐๐/๐๐.
Step 11: Finally, substitute the expression for ๐๐/๐๐ from step 10 into the original relation ๐ฃ๐ = ๐๐/๐๐. We have ๐ฃ๐ = ๐๐/๐๐ = ๐๐/๐๐.
Therefore, we have shown that the relation ๐ฃ๐ = โ๐2 ๐๐/๐๐ is true for the group velocity.
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