A drag racer starts from rest and accelerates at 9 m/s2 for the entire distance of 350 m. What is the velocity of the race car at the end of the run?Select one:a.79 m/sb.40 m/sc.95 m/sd.59 m/se.67 m/s
Question
A drag racer starts from rest and accelerates at 9 m/s2 for the entire distance of 350 m. What is the velocity of the race car at the end of the run?Select one:a.79 m/sb.40 m/sc.95 m/sd.59 m/se.67 m/s
Solution
To solve this problem, we can use the equation of motion that relates final velocity (v), initial velocity (u), acceleration (a), and distance (s). The equation is:
v^2 = u^2 + 2as
Given in the problem, the drag racer starts from rest, so the initial velocity (u) is 0. The acceleration (a) is 9 m/s^2 and the distance (s) is 350 m. Substituting these values into the equation gives:
v^2 = 0 + 29350 v^2 = 6300
Taking the square root of both sides to solve for v gives:
v = sqrt(6300) = 79.37 m/s
So, the velocity of the race car at the end of the run is approximately 79 m/s. Therefore, the answer is a. 79 m/s.
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