Sure, here is a simple C++ program that calculates the sum of even and odd numbers up to a given number 'n'. ```cpp #include using namespace std; int main() { int n, sumEven = 0, sumOdd = 0; cout n; for(int i = 1; i

Question

Sure, here is a simple C++ program that calculates the sum of even and odd numbers up to a given number 'n'.

#include<iostream>
using namespace std;

int main() {
    int n, sumEven = 0, sumOdd = 0;

    cout << "Enter a number: ";
    cin >> n;

    for(int i = 1; i <= n; i++) {
        if(i % 2 == 0)
            sumEven += i;
        else
            sumOdd += i;
    }

    cout << "Sum of even numbers: " << sumEven << endl;
    cout << "Sum of odd numbers: " << sumOdd << endl;

    return 0;
}

This program works as follows:

It first asks the user to enter a number 'n'.
It then initializes two variables, sumEven and sumOdd, to 0. These variables will hold the sum of the even and odd numbers, respectively.
It then enters a loop that runs from 1 to 'n'. For each number 'i' in this range, it checks if 'i' is even or odd by using the modulus operator (i % 2).
If 'i' is even (i.e., i % 2 == 0), it adds 'i' to sumEven. Otherwise, it adds 'i' to sumOdd.
After the loop finishes, it prints the sum of the even and odd numbers.

Knowee AI · Accepted Answer

Sure, here is a simple C++ program that calculates the sum of even and odd numbers up to a given number 'n'.

#include<iostream>
using namespace std;

int main() {
    int n, sumEven = 0, sumOdd = 0;

    cout << "Enter a number: ";
    cin >> n;

    for(int i = 1; i <= n; i++) {
        if(i % 2 == 0)
            sumEven += i;
        else
            sumOdd += i;
    }

    cout << "Sum of even numbers: " << sumEven << endl;
    cout << "Sum of odd numbers: " << sumOdd << endl;

    return 0;
}

This program works as follows:

It first asks the user to enter a number 'n'.
It then initializes two variables, sumEven and sumOdd, to 0. These variables will hold the sum of the even and odd numbers, respectively.
It then enters a loop that runs from 1 to 'n'. For each number 'i' in this range, it checks if 'i' is even or odd by using the modulus operator (i % 2).
If 'i' is even (i.e., i % 2 == 0), it adds 'i' to sumEven. Otherwise, it adds 'i' to sumOdd.
After the loop finishes, it prints the sum of the even and odd numbers.

Write a C++ program to find the sum of even and odd n natural numbers

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