To solve this problem, we can use a loop to iterate through the first N odd numbers and calculate their sum. Here is the step-by-step solution:

1. Read the value of N from the user.
2. Initialize a variable named "sum" to 0 to store the sum of the odd numbers.
3. Initialize a variable named "count" to 0 to keep track of the number of odd numbers encountered.
4. Start a loop that iterates from 1 until the count reaches N.
5. Inside the loop, check if the current number is odd by using the modulo operator (%). If the number modulo 2 is not equal to 0, it is odd.
6. If the number is odd, add it to the sum variable and increment the count by 1.
7. After the loop ends, print the value of the sum variable as the output.

Here is the code implementation in Python:

```python
N = int(input("Enter the value of N: "))
sum = 0
count = 0

for num in range(1, N*2, 2):
sum += num
count += 1
if count == N:
break

print("Sum of first", N, "odd numbers:", sum)
```

This program prompts the user to enter the value of N, calculates the sum of the first N odd numbers, and then prints the result.

Question

To solve this problem, we can use a loop to iterate through the first N odd numbers and calculate their sum. Here is the step-by-step solution:

1. Read the value of N from the user.
2. Initialize a variable named "sum" to 0 to store the sum of the odd numbers.
3. Initialize a variable named "count" to 0 to keep track of the number of odd numbers encountered.
4. Start a loop that iterates from 1 until the count reaches N.
5. Inside the loop, check if the current number is odd by using the modulo operator (%). If the number modulo 2 is not equal to 0, it is odd.
6. If the number is odd, add it to the sum variable and increment the count by 1.
7. After the loop ends, print the value of the sum variable as the output.

Here is the code implementation in Python:

```python
N = int(input("Enter the value of N: "))
sum = 0
count = 0

for num in range(1, N*2, 2):
    sum += num
    count += 1
    if count == N:
        break

print("Sum of first", N, "odd numbers:", sum)
```

This program prompts the user to enter the value of N, calculates the sum of the first N odd numbers, and then prints the result.

Knowee AI · Accepted Answer

To solve this problem, we can use a loop to iterate through the first N odd numbers and calculate their sum. Here is the step-by-step solution:

1. Read the value of N from the user.
2. Initialize a variable named "sum" to 0 to store the sum of the odd numbers.
3. Initialize a variable named "count" to 0 to keep track of the number of odd numbers encountered.
4. Start a loop that iterates from 1 until the count reaches N.
5. Inside the loop, check if the current number is odd by using the modulo operator (%). If the number modulo 2 is not equal to 0, it is odd.
6. If the number is odd, add it to the sum variable and increment the count by 1.
7. After the loop ends, print the value of the sum variable as the output.

Here is the code implementation in Python:

```python
N = int(input("Enter the value of N: "))
sum = 0
count = 0

for num in range(1, N*2, 2):
    sum += num
    count += 1
    if count == N:
        break

print("Sum of first", N, "odd numbers:", sum)
```

This program prompts the user to enter the value of N, calculates the sum of the first N odd numbers, and then prints the result.

Write a program to accept an integer N and print the sum of first N odd numbersInput Format:An integer range is given inputOutput Format:Print only calculated sum.Constraints:1 <= N <= 10^16 Sample Input 1:2Sample Output 1:4Sample Input 2:10Sample Output 2:100

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