The current in a coil of inductance 5H decreases at the rate of 2A/s. The induced e.m.f is
Question
The current in a coil of inductance 5H decreases at the rate of 2A/s. The induced e.m.f is
Solution
The induced electromotive force (emf) in a coil can be calculated using Faraday's law of electromagnetic induction, which states that the induced emf is equal to the rate of change of magnetic flux.
The formula for calculating the induced emf (E) is:
E = -L * (dI/dt)
where:
- L is the inductance of the coil, and
- dI/dt is the rate of change of current.
Given that the inductance (L) is 5H and the rate of change of current (dI/dt) is -2A/s (the negative sign indicates that the current is decreasing), we can substitute these values into the formula:
E = -5H * -2A/s
Multiplying these values gives:
E = 10V
Therefore, the induced emf is 10 volts.
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