A coil induces 350 mV when the current changes at the rate of 1 A/s. The value of inductance is:a.350mHb.250mHc.150mHd.3,500mH
Question
A coil induces 350 mV when the current changes at the rate of 1 A/s. The value of inductance is:a.350mHb.250mHc.150mHd.3,500mH
Solution
The inductance (L) of a coil can be calculated using Faraday's law of electromagnetic induction, which states that the induced voltage (V) in a coil is equal to the rate of change of current (dI/dt) times the inductance (L). This can be written as:
V = L * (dI/dt)
Rearranging for L gives:
L = V / (dI/dt)
Given: V = 350 mV = 0.35 V (since 1 V = 1000 mV), dI/dt = 1 A/s.
Substituting these values into the formula, we get:
L = 0.35 V / 1 A/s L = 0.35 H
Since 1 H = 1000 mH, we can convert this to millihenries:
L = 0.35 H * 1000 mH/H L = 350 mH
So, the inductance of the coil is 350 mH. Therefore, the correct answer is a. 350 mH.
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