The magnetic flux linked with a coil changes by 2×10-2Wb when the currentchanges by 0.01A. The self inductance of the coil is
Question
The magnetic flux linked with a coil changes by 2×10-2Wb when the currentchanges by 0.01A. The self inductance of the coil is
Solution
The self-inductance of a coil is defined as the ratio of the magnetic flux to the current. It is given by the formula:
L = ΔΦ/ΔI
where: L is the self-inductance, ΔΦ is the change in magnetic flux, and ΔI is the change in current.
Given that ΔΦ = 2×10^-2 Wb and ΔI = 0.01 A, we can substitute these values into the formula to find the self-inductance:
L = (2×10^-2 Wb) / (0.01 A) = 2 H
So, the self-inductance of the coil is 2 Henry.
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