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The magnetic flux linked with a coil at any instant 't' is given by ϕ = 5t3 – 100t + 300, the e.m.f. induced in the coil at t = 2 second is :-–40 V40 V140 V300 V

Question

The magnetic flux linked with a coil at any instant 't' is given by ϕ = 5t3 – 100t + 300, the e.m.f. induced in the coil at t = 2 second is :-–40 V40 V140 V300 V

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Solution

To find the e.m.f. induced in the coil at t = 2 seconds, we need to substitute t = 2 into the equation for magnetic flux.

Given: ϕ = 5t^3 - 100t + 300

Substituting t = 2 into the equation: ϕ = 5(2)^3 - 100(2) + 300 ϕ = 5(8) - 200 + 300 ϕ = 40 - 200 + 300 ϕ = 140

Therefore, the e.m.f. induced in the coil at t = 2 seconds is 140 V.

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