A coil of area 50 centimeter square has 1000 turns and the magnetic field of 0.2 T is parallel to the coil, if the magnetic field is reduced to zero in 2 second, the induced emf in the coil is___________*1 point0 V1 V10 V5 V

The induced emf in a coil can be calculated using Faraday's law of electromagnetic induction, which states that the induced emf is equal to the rate of change of magnetic flux.

The magnetic flux (Φ) through the coil is given by the product of the magnetic field strength (B), the area of the coil (A), and the cosine of the angle between the magnetic field and the normal to the coil (cosθ). In this case, the magnetic field is parallel to the coil, so θ = 0 and cosθ = 1.

So, Φ = B * A * cosθ = B * A.

The change in magnetic flux (ΔΦ) is then the final flux minus the initial flux. The final flux is zero (because the magnetic field is reduced to zero), and the initial flux is B * A.

So, ΔΦ = 0 - B * A = -B * A.

The rate of change of magnetic flux (dΦ/dt) is then ΔΦ divided by the change in time (Δt), which is 2 seconds in this case.

So, dΦ/dt = ΔΦ / Δt = -B * A / Δt.

Finally, the induced emf (ε) is equal to the negative of the rate of change of magnetic flux, multiplied by the number of turns in the coil (N).

So, ε = -N * dΦ/dt = -N * (-B * A / Δt) = N * B * A / Δt.

Substituting the given values:

ε = 1000 turns * 0.2 T * 50 cm² / 2 s.

But we need to convert the area from cm² to m² (since the standard unit of magnetic field strength is T (tesla), which is equivalent to N/(A*m), and 1 m² = 10,000 cm²):

So, A = 50 cm² * (1 m² / 10,000 cm²) = 0.005 m².

Substituting this back in:

ε = 1000 turns * 0.2 T * 0.005 m² / 2 s = 0.5 V.

So, the induced emf in the coil is 0.5 V.