Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, minus, 3, x, squared, minus, 48, x, minus, 186y=−3x 2 −48x−186
Question
Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, minus, 3, x, squared, minus, 48, x, minus, 186y=−3x 2 −48x−186
Solution
The equation of the axis of symmetry for a parabola given in the form y = ax^2 + bx + c is x = -b/2a.
Given the equation y = -3x^2 - 48x - 186, the coefficients are a = -3 and b = -48.
Substituting these values into the formula gives:
x = -(-48) / 2*(-3) x = 48 / -6 x = -8
So, the equation of the axis of symmetry of the given parabola is x = -8.
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