Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, x, squared, minus, 2, x, plus, 1y=x 2 −2x+1
Question
Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, x, squared, minus, 2, x, plus, 1y=x 2 −2x+1
Solution
The equation of the axis of symmetry for a parabola given in the form y = ax^2 + bx + c is x = -b/2a.
In the equation y = x^2 - 2x + 1, a = 1 and b = -2.
Substituting these values into the formula, we get:
x = -(-2)/2(1) x = 2/2 x = 1
So, the equation of the axis of symmetry of the parabola y = x^2 - 2x + 1 is x = 1.
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