Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, minus, 2, x, squared, plus, 8, x, plus, 6y=−2x 2 +8x+6
Question
Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, minus, 2, x, squared, plus, 8, x, plus, 6y=−2x 2 +8x+6
Solution
The equation of the axis of symmetry for a parabola given in the form y = ax^2 + bx + c is x = -b/2a.
In the given equation y = -2x^2 + 8x + 6, the coefficient a is -2 and the coefficient b is 8.
Substituting these values into the formula, we get:
x = -b/2a x = -8/(2*-2) x = -8/-4 x = 2
So, the equation of the axis of symmetry of the given parabola is x = 2.
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