A hydraulic jack having a ram 250 mm in diameter lifts a weight W = 40 kN under theaction of a 35 mm plunger. What force is réquired on the plunger to lift the weight?
Question
A hydraulic jack having a ram 250 mm in diameter lifts a weight W = 40 kN under theaction of a 35 mm plunger. What force is réquired on the plunger to lift the weight?
Solution
To solve this problem, we need to use Pascal's law, which states that when there is an increase in pressure at any point in a confined fluid, there is an equal increase at every other point in the container.
Step 1: Calculate the area of the ram and the plunger.
The area (A) of a circle is given by the formula A = πr², where r is the radius. The radius is half the diameter.
The area of the ram (A1) is A1 = π * (250 mm / 2)² = 49087.3 mm².
The area of the plunger (A2) is A2 = π * (35 mm / 2)² = 962.1 mm².
Step 2: Use Pascal's law to find the force required on the plunger.
Pascal's law can be written as F1/A1 = F2/A2, where F1 is the force on the ram (which is the weight W), A1 is the area of the ram, F2 is the force on the plunger (which we are trying to find), and A2 is the area of the plunger.
Rearranging the formula to find F2 gives F2 = F1 * (A2/A1).
Substituting the given values gives F2 = 40 kN * (962.1 mm² / 49087.3 mm²) = 0.78 kN.
Therefore, a force of 0.78 kN is required on the plunger to lift the weight.
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