The areas of the piston and ram of a hydraulic press are respectively 0.5 m2 and 10 m2. If a force of 100 N is applied on the piston, the force on the ram is.
Question
The areas of the piston and ram of a hydraulic press are respectively 0.5 m2 and 10 m2. If a force of 100 N is applied on the piston, the force on the ram is.
Solution
The principle of a hydraulic press is based on Pascal's law which states that the pressure applied at one point of the liquid will be the same at all other points in the liquid.
Step 1: Calculate the pressure on the piston. Pressure is defined as force divided by area. So, the pressure on the piston (P1) is the force on the piston (F1) divided by the area of the piston (A1).
P1 = F1 / A1 P1 = 100 N / 0.5 m^2 P1 = 200 Pa (Pascal)
Step 2: Calculate the force on the ram. According to Pascal's law, the pressure on the ram (P2) is equal to the pressure on the piston (P1). The force on the ram (F2) is the pressure on the ram (P2) multiplied by the area of the ram (A2).
F2 = P2 * A2 Since P2 = P1, we can substitute P1 into the equation:
F2 = P1 * A2 F2 = 200 Pa * 10 m^2 F2 = 2000 N
So, the force on the ram is 2000 N.
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