A hydraulic press multiplies force by a factor of 10. If you apply a 20 N force to the small piston, what force will be exerted on the large piston?
Question
A hydraulic press multiplies force by a factor of 10. If you apply a 20 N force to the small piston, what force will be exerted on the large piston?
Solution
The force exerted on the large piston can be calculated by multiplying the force applied on the small piston by the factor by which the hydraulic press multiplies force.
Given: Force applied on the small piston (F1) = 20 N Factor by which force is multiplied (F) = 10
We can use the formula: Force on large piston (F2) = F1 * F
Substituting the given values: F2 = 20 N * 10 = 200 N
So, the force exerted on the large piston will be 200 N.
Similar Questions
If a force 20N is applied to piston C. What is the pressure exerted to piston A Group of answer choices4.0 x 10^2 Pa2.0 x 10^4 Pa4.0 x 10^4 Pa2.0 x 10^2 Pa
A hydraulic press has one piston of diameter 2.0cm and the other piston of diameter 8.0cm. What force (in N) must be applied to the smaller piston to lift an object of mass 700kg at the larger piston?Question 16Answera.300Nb.429Nc.600Nd.200N
The small piston of a hydraulic lift has an area of 0.20 m2 . A car weighing 1.2 x 104 N sits on a rack mounted on the large piston. The large piston has an area of 0.90 m2. How large force must be applied to the small piston to support the car?Group of answer choices2.7 x 10^3 N1.2 x 10^4 N2.1 x 10^3 N2.7 x 10^2 N
The areas of the piston and ram of a hydraulic press are respectively 0.5 m2 and 10 m2. If a force of 100 N is applied on the piston, the force on the ram is.
In a hydraulic machine a force of 0.5N acts normally on the Smaller piston of area 0.1m2. The force that acts on the larger piston whose area is 200m2 will be
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.