The area of cross section of press plunger of a hydraulic press is 4 m2. It is required to overcome a resistive load of 400 kgf on it. Calculate the force required on the pump plunger if the area of cross section of the pump plunger is 0.01 m2.A 6 kgf B 1 kgf C 4 kgf D 16 × 104 kgf
Question
The area of cross section of press plunger of a hydraulic press is 4 m2. It is required to overcome a resistive load of 400 kgf on it. Calculate the force required on the pump plunger if the area of cross section of the pump plunger is 0.01 m2.A 6 kgf B 1 kgf C 4 kgf D 16 × 104 kgf
Solution
The principle of a hydraulic press is based on Pascal's law, which states that the pressure applied at one point of the fluid will be the same at all other points in a closed system.
Given: Area of cross section of press plunger (A1) = 4 m² Resistive load on press plunger (F1) = 400 kgf Area of cross section of pump plunger (A2) = 0.01 m²
We need to find the force required on the pump plunger (F2).
According to Pascal's law, the pressure on both plungers should be the same. Therefore, we can write the equation as:
F1/A1 = F2/A2
Substituting the given values:
400 kgf / 4 m² = F2 / 0.01 m²
Solving for F2:
F2 = (400 kgf / 4 m²) * 0.01 m² = 1 kgf
So, the force required on the pump plunger is 1 kgf. The correct answer is B) 1 kgf.
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