The standard form of a parabola's equation is given by ax^2 + bx + c = 0. To convert the given vertex form x = 8(y - 1)^2 - 15 to the standard form, we need to expand and simplify the equation.

Let's do it step by step:

1. Expand (y - 1)^2 to get y^2 - 2y + 1.
2. Multiply each term by 8 to get 8y^2 - 16y + 8.
3. Subtract 15 from the right side to get x = 8y^2 - 16y - 7.

So, the standard form of the equation is x = 8y^2 - 16y - 7.

Therefore, the correct answer is C. x = 8y^2 - 16y - 7.

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The standard form of a parabola's equation is given by ax^2 + bx + c = 0. To convert the given vertex form x = 8(y - 1)^2 - 15 to the standard form, we need to expand and simplify the equation.

Let's do it step by step:

1. Expand (y - 1)^2 to get y^2 - 2y + 1.
2. Multiply each term by 8 to get 8y^2 - 16y + 8.
3. Subtract 15 from the right side to get x = 8y^2 - 16y - 7.

So, the standard form of the equation is x = 8y^2 - 16y - 7.

Therefore, the correct answer is C. x = 8y^2 - 16y - 7.

Knowee AI · Accepted Answer

The standard form of a parabola's equation is given by ax^2 + bx + c = 0. To convert the given vertex form x = 8(y - 1)^2 - 15 to the standard form, we need to expand and simplify the equation.

Let's do it step by step:

1. Expand (y - 1)^2 to get y^2 - 2y + 1.
2. Multiply each term by 8 to get 8y^2 - 16y + 8.
3. Subtract 15 from the right side to get x = 8y^2 - 16y - 7.

So, the standard form of the equation is x = 8y^2 - 16y - 7.

Therefore, the correct answer is C. x = 8y^2 - 16y - 7.

The vertex form of the equation of a parabola is x = 8(y - 1)2 - 15.What is the standard form of the equation?A.x = 8y2 - 6y - 22B.x = 16y2 - 2y - 16C.x = 8y2 - 16y - 7D.x = 16y2 - 4y + 32SUBMITarrow_backPREVIOUS

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