The magnitude of the current can be calculated using Ohm's law, which states that the current (I) is equal to the power (P) divided by the voltage (V).

In this case, the power (P) is 725 kW or 725,000 W and the voltage (V) is 25,000 V.

So, the current (I) can be calculated as follows:

I = P / V
I = 725,000 W / 25,000 V
I = 29 A

So, the magnitude of the current flowing through the cable is 29 A. Therefore, the correct answer is B. 29 A.

Question

The magnitude of the current can be calculated using Ohm's law, which states that the current (I) is equal to the power (P) divided by the voltage (V).

In this case, the power (P) is 725 kW or 725,000 W and the voltage (V) is 25,000 V.

So, the current (I) can be calculated as follows:

I = P / V
I = 725,000 W / 25,000 V
I = 29 A

So, the magnitude of the current flowing through the cable is 29 A. Therefore, the correct answer is B. 29 A.

Knowee AI · Accepted Answer

The magnitude of the current can be calculated using Ohm's law, which states that the current (I) is equal to the power (P) divided by the voltage (V).

In this case, the power (P) is 725 kW or 725,000 W and the voltage (V) is 25,000 V.

So, the current (I) can be calculated as follows:

I = P / V
I = 725,000 W / 25,000 V
I = 29 A

So, the magnitude of the current flowing through the cable is 29 A. Therefore, the correct answer is B. 29 A.

A low-resistance transmitting cable is used to carry 725 kW of electricity from agenerating station. If the electricity voltage is 25 000 V, what magnitude of currentis flowing through the cable?A. 5.4 AB. 29 AC. 58 AD. 62 A

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