A power cable having a resistance of 200Ω is used to deliver 2.0MW of power at 400kV from a power station to an industrial estate. Calculate the power wasted in the cable.*1 point2,500 W3,000 W5,000 W8,000 W
Question
A power cable having a resistance of 200Ω is used to deliver 2.0MW of power at 400kV from a power station to an industrial estate. Calculate the power wasted in the cable.*1 point2,500 W3,000 W5,000 W8,000 W
Solution
To calculate the power wasted in the cable, we can use the formula for power loss in a resistor, which is P = I^2 * R, where P is power, I is current, and R is resistance.
First, we need to find the current (I) in the cable. We can use the formula P = IV, where P is power and V is voltage. Rearranging for I gives us I = P/V.
Given that the power (P) is 2.0MW (or 2,000,000W) and the voltage (V) is 400kV (or 400,000V), we can substitute these values into the formula to find the current:
I = 2,000,000W / 400,000V = 5A
Now that we have the current, we can substitute this value and the given resistance (R = 200Ω) into the formula for power loss to find the power wasted in the cable:
P = I^2 * R = (5A)^2 * 200Ω = 25A^2 * 200Ω = 5,000W
So, the power wasted in the cable is 5,000W.
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