A transmission line cable consists of 26 strands of identical copper conductors, each 1.255 mm in diameter. The length of the cable is 10 km, but because of the twist of the strands, the actual length of each conductor is increased by 5%. If the resistivity of the copper is 1.72 x 10-8 Ω.m, what is the resistance of the cable in ohms?
Question
A transmission line cable consists of 26 strands of identical copper conductors, each 1.255 mm in diameter. The length of the cable is 10 km, but because of the twist of the strands, the actual length of each conductor is increased by 5%. If the resistivity of the copper is 1.72 x 10-8 Ω.m, what is the resistance of the cable in ohms?
Solution 1
To solve this problem, we need to use the formula for resistance, which is:
R = ρ * (L/A)
where:
- R is the resistance,
- ρ is the resistivity,
- L is the length of the conductor, and
- A is the cross-sectional area of the conductor.
Step 1: Calculate the cross-sectional area of one strand. The cross-sectional area (A) of a circular conductor is given by the formula A = π * (d/2)^2, where d is the diameter of the conductor. Substituting the given diameter:
A = π * (1.255 x 10^-3 m / 2)^2 = 1.236 x 10^-6 m^2
Step 2: Calculate the total cross-sectional area. Since there are 26 strands, the total cross-sectional area is 26 * A = 26 * 1.236 x 10^-6 m^2 = 3.2136 x 10^-5 m^2
Step 3: Calculate the length of the conductor. The actual length of each conductor is increased by 5%, so the length of one conductor is 10 km * 1.05 = 10.5 km = 10.5 x 10^3 m.
Step 4: Calculate the resistance. Substitute the values into the resistance formula:
R = ρ * (L/A) = 1.72 x 10^-8 Ω.m * (10.5 x 10^3 m / 3.2136 x 10^-5 m^2) = 5.63 Ω
So, the resistance of the cable is approximately 5.63 ohms.
Solution 2
To solve this problem, we need to follow these steps:
-
Calculate the cross-sectional area of one strand: The formula for the area of a circle is A = πr². The radius is half the diameter, so r = 1.255 mm / 2 = 0.6275 mm = 0.0006275 m. Therefore, A = π * (0.0006275 m)² = 1.237 x 10^-6 m².
-
Calculate the total cross-sectional area of all strands: Since there are 26 strands, the total area is 26 * 1.237 x 10^-6 m² = 3.2162 x 10^-5 m².
-
Calculate the length of one strand: The length of the cable is increased by 5% due to the twist of the strands, so the actual length is 10 km * 1.05 = 10.5 km = 10500 m.
-
Calculate the resistance of the cable: The formula for resistance is R = ρL/A, where ρ is resistivity, L is length, and A is area. Substituting the given values, we get R = 1.72 x 10^-8 Ω.m * 10500 m / 3.2162 x 10^-5 m² = 0.056 Ω.
So, the resistance of the cable is 0.056 ohms.
Similar Questions
A copper wire has diameter 0.5 mm and resistivity of 1.6 x 10-8 Ω m. What will be the length of this wire to make its resistance 10 Ω ? How much does the resistance change if the diameter is doubled
The resistance of a wire of 0.01 cm radius is 10 Ω. If the resistivity of the material of the wire is 50 × 10-8 ohm meter, find the length of the wire.
The resistance of a wire is 5 Ω. Its new resistance in ohm, if stretched to 5 times of its original length will be :
A copper wire has a resistivity of 1.723 x 10-8 Ω-m and a cross-sectional area of 9.5 mm2. Calculate the length of the wire in m when its resistance is 3.2 Ω.
1One metre of a particular type of wire has a resistance of 30 Ω. What length of this wire will have a resistance of 6 Ω?20 m180 m20 cm24 cm2Which of the following will cause the resistance of a piece of wire to increase?Increasing its lengthDecreasing its temperatureDecreasing its lengthConnecting it in series to a fixed resistor3A 10 cm-long piece of wire has a resistance of 1.2 Ω. Calculate the resistance of a 70 cm-long piece of wire which is made from the same material, has the same cross-sectional area and is at the same temperature?8.4 Ω12 Ω700 Ω0.17 Ω4Three resistors have resistances of 10, 20 and 30 Ω. Calculate their total resistance when connected in series.60 Ω0 Ω5.45 Ω6000 Ω5When two resistors are connected in series, their total resistance is 100 Ω. What can be said about their total resistance when they are connected in parallel?It will be greater than 100 ΩIt will be equal to zeroIt will be equal to 100 ΩIt will be less than 100 Ω
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.