Given a string of lower case letters in the range ascii[a-z], identify the index of character to be removed to change the string into a palindrome. If the string cannot be converted to palindrome or is already a palindrome just return -1 else return index of the character to be removed.
Question
Given a string of lower case letters in the range ascii[a-z], identify the index of character to be removed to change the string into a palindrome. If the string cannot be converted to palindrome or is already a palindrome just return -1 else return index of the character to be removed.
Solution
Sure, here is a Python solution for the problem:
def find_index(s):
# Check if the string is already a palindrome
if s == s[::-1]:
return -1
# Iterate over the string
for i in range(len(s)):
# Remove the character at index i
t = s[:i] + s[i+1:]
# Check if the new string is a palindrome
if t == t[::-1]:
return i
# If no palindrome can be formed by removing a character
return -1
This function works by first checking if the input string s is already a palindrome. If it is, it returns -1. If not, it iterates over each character in the string, removes it, and checks if the resulting string is a palindrome. If it is, it returns the index of the removed character. If no palindrome can be formed by removing a single character, it returns -1.
Similar Questions
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